Below you will find the discussion and relevant materials for the ES 105 homework assignment due on March 09, 2009.
Discussion
ES105 - Winter, 2009 Find the Crack (Note: All (x,y) units in this problem are stated in the units of the .nod file.) Continuation of Homeworks 5 and 6. The node and element files are the same, Problem 44. BUT -- there is a crack in the plate! And it leaks current. The crack is located between zones 1 and 2 of the element file; it runs from top to bottom, without interruption. It is imperfectly grounded, resulting in a leak of current out of the system. It is to be modeled as a set of point sinks of current, proportional to the local voltage. div (t grad U) = Sum_m ( k U delta_m ) where U is the voltage, delta_m is the Dirac delta function concentrated at node m along the crack. The coefficient k is uniform along the crack. Everything else from Problem 44 is unchanged -- the ground nodes, the point source, and the boundary efflux. The current leak along the crack is new. Truth 1. The boundary element file hw44.bel shows the boundaries among 3 zones: 0 (outside), 1 and 2. All the 'crack' nodes are on the 1-2 boundary. Find and save them. ANSWER: In the range of 0.01-0.001. Nevertheless, this is always dependant on the sensitivity of the instrumentation used to gather information.
ANSWER: k_inf ~100.0 & k=k_inf/10=10.0
Inversion 1. Invert perfect data for the nodal sources. Use Representer method as you did in HW6; compute the bias in U. 1. Voltage (U) 4.Do the MonteCarlo results agree with the direct results?
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MaterialsSource Code |
PlotsSolution using SOLVE @ k=0
Difference Map between: SOLVE @ k=0 & SOLVE @ k=0.01 i.e., k is "practically" zero depending on instrument sensitivity
Difference Map between: SOLVE @ k=0 & SOLVE @ k=0.001 i.e., k is "practically" zero depending on instrument sensitivity
Solution using SOLVE @ k=10.0 i.e., k=k_inf/10
Difference Map between: SOLVE @ k=0 & SOLVE @ k=10.0 i.e. k=k_inf/10
Difference Map between: SOLVE @ k=0 & SOLVE @ k=100.0 i.e., k is "practically" infinite
Solution using REPRESENTER's to INVERT DATA (@ k=10)
Difference Map between Solutions using SOLVE.F and REPRESENTERs
RHS using REPRESENTER's to INVERT DATA
INVERSE NOISE using REPRESENTER's to INVERT DATA
Monte Carlo Simulation SOLUTION k=10 and 5000 iterations
RHS (SOURCES) k=10 and 5000 iterations
BIAS k=10 and 5000 iterations
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